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Postby FabensMath » Tue May 15, 2012 4:31 pm

\displaystyle \frac{d_1+d_2}{2}=x \ and \ x-d_1=y

\displaystyle \frac{1}{2} \left| 60H-11M \right| = \theta

\sqrt{x^2+y^2-2\cdot x \cdot y \cdot cos(\theta)} = D
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 4:36 pm

\displaystyle \frac{ft^2/h}{min./60} = r_1

\displaystyle solve(r_1x + ft = r_2x,x) \to x= hr.
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 4:41 pm

\displaystyle x=acres/ \ y = rows
\displaystyle z = ft \ apart/ \ t = diameter

\displaystyle \frac{22\pi t y \sqrt{10x}}{z}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 4:43 pm

\displaystyle \frac{mph^2}{ \frac{32.17}{5280} \cdot 3600^2}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 4:46 pm

\displaystyle \sqrt{ mi^2 + (2\cdot mph \cdot hr \cdot sin(\theta))^2}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 4:50 pm

\displaystyle 100 \cdot \frac{ (\%)^2}{1-(1-\%)^2}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 5:13 pm

\HUGE \displaystyle \frac{gal_{n} \cdot 128 \cdot \frac{oz_{dye}}{gal_{stock}\cdot 128-oz_{dye}}}{8}
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Postby FabensMath » Tue May 15, 2012 5:14 pm

\displaystyle \frac{mph_1}{s_1} = \frac{mph_2}{s_2}
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Postby FabensMath » Tue May 15, 2012 5:17 pm

\displaystyle \left( \frac{60}{min +\frac{s}{60}} \right) \left( \frac{mi}{mph.} \right)
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 5:25 pm

\displaystyle solve(x^2+y^2 = r^2 ,x) | y=mx+b \to x_1 \ and \ x_2

\displaystyle \sqrt{(m^2+1)(x_2-x_1)^2}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 5:28 pm

\displaystyle 2\cdot cos^{-1} \left( \frac{d}{D} \right) = \theta

\displaystyle 100 \cdot \frac{D^2 (\theta - sin(\theta))}{2 \pi (D^2-d^2)}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 6:02 pm

\displaystyle \frac{v^2}{tv -x} \cdot \frac{5280}{3600^2}
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 6:25 pm

\displaystyle solve(m_1 - m_2 = 2x \sin \left( \frac{\theta}{2} \right) ,x) | \theta = \frac{m_1}{x} \to x

\displaystyle solve( m_1 - m_2 = 2x \sin \left( \frac{\theta}{2} \right), \theta)

\displaystyle d - \left(r - r\cdot cos \left( \frac{\theta}{2} \right) \right)
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Re: Posts here evaporate...

Postby FabensMath » Tue May 15, 2012 6:35 pm

\displaystyle \% Error = 100\cdot \left(\frac{A}{E} -1\right)
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 6:45 pm

\HUGE \displaystyle solve(1 - \%_2 = \%_1 \wedge (x/d) , x )

\HUGE \displaystyle solve(1 - \%_2 = \%_1 ^ {(\frac{x}{d})} , x )
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 6:47 pm

\HUGE \displaystyle \frac{(\sqrt{x - y} - \sqrt{x+y})^2}{2}
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 6:52 pm

\HUGE \displaystyle 100\cdot \frac{D^2(\theta - sin(\theta))}{2 \pi (D^2 - d^2)} | \theta = 2\cdot \cos^{-1} \left( \frac{d}{D} \right)
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 6:55 pm

\HUGE \displaystyle \sqrt{32.17d}
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 7:02 pm

\HUGE \displaystyle 100\cdot \left( \frac{5x^2-4xy+2y^2}{6x^2 - 8xy +5y^2} -1 \right)
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 7:05 pm

\HUGE \displaystyle \frac{V\sqrt{2\cdot 32.17 d}}{32.17} | V = ft/s
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 7:25 pm

\HUGE \displaystyle \frac{a\cdot t_2}{2(t_1+t_2)}
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 7:37 pm

\HUGE \displaystyle \frac{-(y - z)}{x-y}
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 10:19 pm

\HUGE \displaystyle \frac{ \sqrt{x^2+y^2}}{2}
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 10:28 pm

\HUGE \displaystyle \frac{3960}{cos( \frac{x}{2 \cdot 3960} ) } - 3960
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Re: Posts here evaporate...

Postby FabensMath » Tue Jun 19, 2012 10:36 pm

\HUGE \displaystyle \frac{5\pi x}{88y}
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